passage paramètre valeur par défaut

Problème de code
Rappel 

function selectEntries(options) {
    options = options || {};
    var start = options.start || 0;
    var end = options.end || getDbLength();
    var step = options.step || 1;
    ···
}

In ECMAScript 6, you can use destructuring, which looks like this:

function selectEntries({ start=0, end=-1, step=1 }) {
    ···
};

If you call selectEntries() with zero arguments, the destructuring fails, because you can’t match an object pattern against undefined. That can be fixed via a default value. In the following code, the object pattern is matched against {} if there isn’t at least one argument.

function selectEntries({ start=0, end=-1, step=1 } = {}) {
    ···
};

let tabPers = [
  {
    nom: "Brusel",
    sex : "h",
    born: 1980,
n:"fr"
  },
  {
    nom: "Charles",
    sex : "h",
    born: 2001,
n:"fr"
  },
  {
    nom: "Dupont",
    sex : "f",
    born: 2000,
n:"fr"
  },  
 {
    nom: "Toto",
    sex : "f",
    born: 1991,
n:"fr"
  },
  {
    nom: "Dupont",
    sex : "h",
    born: 2002,
n:"fr"
  },
];

let annee = new Date().getFullYear();
function setAge({nom,sex,born}) {
age = annee - born;
  return {nom,sex,age};
}
function setAge({nom,sex,born}) {
age = annee - born;
  return {nom,sex,age};
}


function filterMultArg(array, test,argObj) {
  let passed = [];
  for (val of array) {
    if (test(val, argObj ))
      passed.push(val);
  }
  return passed;
}

function sexAge({sex,age},  {limiteAge=18,civilite="h"} = {} ) {
    console.log(limiteAge,civilite);
    return (sex === civilite  && age > limiteAge);
}
function transf(array, fx) {
  let passed = [];
  
  for(v  of array)
passed.push(fx(v));

  return passed;
}


T = transf(tabPers,setAge);
console.log(filterMultArg(T, sexAge,{limiteAge:2,civilite:"h",pipo:"popi"}));
console.log(filterMultArg(T, sexAge,{pipo:"popi"}));
console.log(filterMultArg(T, sexAge));